Optimal. Leaf size=141 \[ \frac {2 \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c} \tan (e+f x)}{\sqrt {a \sec (e+f x)+a} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f}-\frac {\sqrt {2} \sqrt {c-d} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c-d} \tan (e+f x)}{\sqrt {2} \sqrt {a \sec (e+f x)+a} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f} \]
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Rubi [A] time = 0.37, antiderivative size = 141, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, integrand size = 29, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.138, Rules used = {3935, 3934, 203, 3983} \[ \frac {2 \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c} \tan (e+f x)}{\sqrt {a \sec (e+f x)+a} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f}-\frac {\sqrt {2} \sqrt {c-d} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c-d} \tan (e+f x)}{\sqrt {2} \sqrt {a \sec (e+f x)+a} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f} \]
Antiderivative was successfully verified.
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Rule 203
Rule 3934
Rule 3935
Rule 3983
Rubi steps
\begin {align*} \int \frac {\sqrt {c+d \sec (e+f x)}}{\sqrt {a+a \sec (e+f x)}} \, dx &=\frac {c \int \frac {\sqrt {a+a \sec (e+f x)}}{\sqrt {c+d \sec (e+f x)}} \, dx}{a}+(-c+d) \int \frac {\sec (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}} \, dx\\ &=-\frac {(2 c) \operatorname {Subst}\left (\int \frac {1}{1+a c x^2} \, dx,x,-\frac {\tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{f}+\frac {(2 (c-d)) \operatorname {Subst}\left (\int \frac {1}{2+(a c-a d) x^2} \, dx,x,-\frac {\tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{f}\\ &=\frac {2 \sqrt {c} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c} \tan (e+f x)}{\sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f}-\frac {\sqrt {2} \sqrt {c-d} \tan ^{-1}\left (\frac {\sqrt {a} \sqrt {c-d} \tan (e+f x)}{\sqrt {2} \sqrt {a+a \sec (e+f x)} \sqrt {c+d \sec (e+f x)}}\right )}{\sqrt {a} f}\\ \end {align*}
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Mathematica [A] time = 14.62, size = 184, normalized size = 1.30 \[ \frac {2 \cos \left (\frac {1}{2} (e+f x)\right ) \sqrt {c+d \sec (e+f x)} \left (\frac {\sqrt {2} \sqrt {c} \sqrt {c+d} \sin ^{-1}\left (\frac {\sqrt {2} \sqrt {c} \sin \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c+d}}\right ) \sqrt {\frac {c \cos (e+f x)+d}{c+d}}}{\sqrt {c \cos (e+f x)+d}}+\sqrt {d-c} \tanh ^{-1}\left (\frac {\sqrt {d-c} \sin \left (\frac {1}{2} (e+f x)\right )}{\sqrt {c \cos (e+f x)+d}}\right )\right )}{f \sqrt {a (\sec (e+f x)+1)} \sqrt {c \cos (e+f x)+d}} \]
Antiderivative was successfully verified.
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fricas [A] time = 1.00, size = 883, normalized size = 6.26 \[ \left [\frac {\sqrt {2} \sqrt {-\frac {c - d}{a}} \log \left (\frac {2 \, \sqrt {2} \sqrt {-\frac {c - d}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left (3 \, c - d\right )} \cos \left (f x + e\right )^{2} + 2 \, {\left (c + d\right )} \cos \left (f x + e\right ) - c + 3 \, d}{\cos \left (f x + e\right )^{2} + 2 \, \cos \left (f x + e\right ) + 1}\right ) + 2 \, \sqrt {-\frac {c}{a}} \log \left (-\frac {2 \, \sqrt {-\frac {c}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 2 \, c \cos \left (f x + e\right )^{2} - {\left (c + d\right )} \cos \left (f x + e\right ) + c - d}{\cos \left (f x + e\right ) + 1}\right )}{2 \, f}, \frac {\sqrt {2} \sqrt {-\frac {c - d}{a}} \log \left (\frac {2 \, \sqrt {2} \sqrt {-\frac {c - d}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right ) + {\left (3 \, c - d\right )} \cos \left (f x + e\right )^{2} + 2 \, {\left (c + d\right )} \cos \left (f x + e\right ) - c + 3 \, d}{\cos \left (f x + e\right )^{2} + 2 \, \cos \left (f x + e\right ) + 1}\right ) - 4 \, \sqrt {\frac {c}{a}} \arctan \left (\frac {\sqrt {\frac {c}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{c \sin \left (f x + e\right )}\right )}{2 \, f}, -\frac {\sqrt {2} \sqrt {\frac {c - d}{a}} \arctan \left (-\frac {\sqrt {2} \sqrt {\frac {c - d}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{{\left (c - d\right )} \sin \left (f x + e\right )}\right ) - \sqrt {-\frac {c}{a}} \log \left (-\frac {2 \, \sqrt {-\frac {c}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right ) \sin \left (f x + e\right ) - 2 \, c \cos \left (f x + e\right )^{2} - {\left (c + d\right )} \cos \left (f x + e\right ) + c - d}{\cos \left (f x + e\right ) + 1}\right )}{f}, -\frac {\sqrt {2} \sqrt {\frac {c - d}{a}} \arctan \left (-\frac {\sqrt {2} \sqrt {\frac {c - d}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{{\left (c - d\right )} \sin \left (f x + e\right )}\right ) + 2 \, \sqrt {\frac {c}{a}} \arctan \left (\frac {\sqrt {\frac {c}{a}} \sqrt {\frac {a \cos \left (f x + e\right ) + a}{\cos \left (f x + e\right )}} \sqrt {\frac {c \cos \left (f x + e\right ) + d}{\cos \left (f x + e\right )}} \cos \left (f x + e\right )}{c \sin \left (f x + e\right )}\right )}{f}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {d \sec \left (f x + e\right ) + c}}{\sqrt {a \sec \left (f x + e\right ) + a}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [B] time = 1.88, size = 494, normalized size = 3.50 \[ -\frac {2 \sqrt {\frac {d +c \cos \left (f x +e \right )}{\cos \left (f x +e \right )}}\, \sqrt {\frac {a \left (1+\cos \left (f x +e \right )\right )}{\cos \left (f x +e \right )}}\, \cos \left (f x +e \right ) \left (-1+\cos \left (f x +e \right )\right ) \left (\ln \left (-\frac {\sqrt {c -d}\, \cos \left (f x +e \right )-\sin \left (f x +e \right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}-\sqrt {c -d}}{\sin \left (f x +e \right )}\right ) c^{3}-3 \ln \left (-\frac {\sqrt {c -d}\, \cos \left (f x +e \right )-\sin \left (f x +e \right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}-\sqrt {c -d}}{\sin \left (f x +e \right )}\right ) c^{2} d +3 \ln \left (-\frac {\sqrt {c -d}\, \cos \left (f x +e \right )-\sin \left (f x +e \right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}-\sqrt {c -d}}{\sin \left (f x +e \right )}\right ) c \,d^{2}-\ln \left (-\frac {\sqrt {c -d}\, \cos \left (f x +e \right )-\sin \left (f x +e \right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}-\sqrt {c -d}}{\sin \left (f x +e \right )}\right ) d^{3}+\sqrt {2}\, \sqrt {-\left (c -d \right )^{4} c}\, \arctan \left (\frac {\left (-1+\cos \left (f x +e \right )\right ) \left (c -d \right )^{2} c \sqrt {2}}{\sin \left (f x +e \right ) \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}\, \sqrt {-\left (c -d \right )^{4} c}}\right ) \sqrt {c -d}\right )}{f \sin \left (f x +e \right )^{2} \sqrt {-\frac {2 \left (d +c \cos \left (f x +e \right )\right )}{1+\cos \left (f x +e \right )}}\, a \sqrt {c -d}\, \left (c^{2}-2 c d +d^{2}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {\sqrt {c+\frac {d}{\cos \left (e+f\,x\right )}}}{\sqrt {a+\frac {a}{\cos \left (e+f\,x\right )}}} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\sqrt {c + d \sec {\left (e + f x \right )}}}{\sqrt {a \left (\sec {\left (e + f x \right )} + 1\right )}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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